How many grams of NaOH are dissolved in order to create 750 ml of a 0.1 M solution?

In order to create 750 ml of a 0. 1 M solution of NaOH, 75. 00 g of the compound must be dissolved. To calculate this amount, use the formula: mass (g) = molarity (M) x volume (L) x molar mass (g/mol).

In this case, the molar mass of NaOH is 40. 00 g/mol, so the calculation would be 0. 1 M x 0. 750 L x 40. 00 g/mol = 75. 00 g. This means that 75. 00 g of NaOH must be dissolved in order to create 750 ml of a 0.

1 M solution.

How do you make a 0.1 M solution of NaOH?

To make a 0. 1 M solution of NaOH, you will need to accurately weigh out 0. 10 moles of sodium hydroxide, also known as NaOH. Because the molar mass of NaOH is approximately 40 grams/mole, you need to weigh out 4.

0 grams of NaOH. Put the NaOH into a 1 liter volumetric flask, add 500 milliliters of pure water, and then fill the volumetric flask to the 1 liter mark with pure water. Label the flask with the concentration and your initials and shake or swirl to dissolve the NaOH.

Once it has dissolved, you have your 0. 1 molar solution of NaOH.

How can you prepare 500 ml of 0.1 N NaOH solution?

To prepare 500 ml of 0. 1N NaOH solution, you will need to gather a weighing balance, 500ml of distilled water, and a calculated amount of sodium hydroxide. To begin, you will need to weigh out 0. 85 g of sodium hydroxide.

You can then place the weighed out sodium hydroxide in a 500 ml beaker or other volumetric container. Once the sodium hydroxide is in the container, you can add the distilled water until it is approximately 450 ml.

After that is done, you can then stir the mixture until it is completely dissolved. Once it is dissolved, you can fill the container up to the 500 ml mark with more distilled water. This will give you a total of 500 ml of solution with a concentration of 0.

1 N NaOH.

How many grams of NaOH do I have to weigh to make 0.1 moles?

In order to determine the number of grams of NaOH you need to weigh to make 0. 1 moles, you will need to convert the number of moles (0. 1) to grams, which is the mass unit associated with the number of moles.

In order to do this, you will need to use the molar mass of NaOH, which is equal to 40. 00 g/mol. This means that, for each mole of NaOH, there will be 40 g of NaOH. Therefore, if you have 0. 1 moles of NaOH, in terms of mass, this would be the equivalent of 4 g (0.

1 × 40. 00 g/mol = 4. 00 g). Thus, you must weigh out 4 g of NaOH in order to produce 0. 1 moles.

How can we prepare a 0.1 M NaOH solution in 500 ml of distilled water?

To prepare a 0. 1 M NaOH solution in 500 ml of distilled water, you will need a scale, a volumetric flask, and some NaOH pellets. Begin by weighing out 0. 5425 grams of NaOH pellets on the scale. Transfer these pellets to the volumetric flask, then add 500 ml of distilled water.

Gently swirl or shake the flask until all of the pellets have been dissolved. You can then use the flask to make sure that the laboratory volume is exactly 500 ml. Make sure the lab temperature is the same as the temperature at which the NaOH was dissolved.

Finally, label the flask with the name of the solution and the date it was prepared.

How do you calculate 0.1 NaOH?

To calculate 0.1 NaOH (sodium hydroxide), you can use the formula:

M = L / 14. To calculate it, start by finding the molarity (M), which is the number of moles of solute (in this case NaOH) per liter of solution. To do this, you need to know the volume of the solution (L) and the weight of NaOH required to make the solution.

To find the volume, you need to use the formula V = Mass (g) / Density, where Density equals 2.13g/mL for 0.1 NaOH. Once you have the volume, you can feed that into the formula M = L / 14.

For example, if you needed 2g of 0. 1 NaOH, you would first calculate the volume using the density: V = 2g / 2. 13mL =. 939 mL. Then you would convert this to liters by dividing by 1,000: L =. 939mL / 1,000 =.

000939 L. Finally, you plug these two numbers into the formula M = L / 14 to get the molarity of 0. 1 NaOH: M =. 000939L / 14 = 0. 000671M.

What is 0.1 N NaOH?

0. 1 N NaOH is a very dilute aqueous solution of sodium hydroxide, with a concentration of 0. 1 moles per litre. It is prepared by adding 0. 1 moles of NaOH in one litre of deionized water. The final solution is then neutralised with hydrochloric acid if necessary, to adjust pH value to 7.

0. 0. 1 N NaOH is used in a range of activities, such as in the titration of acids, in water purification, and in the manufacture of soaps and detergents. It can also be used to test for the presence of heavy metals in a solution, and for cleaning laboratory glassware.

When using 0. 1 N NaOH, it is important not to spill it and to ensure that it is handled with proper protective wear such as gloves and protective eyewear.

What is the weight of NaOH in 100 ml 0.1 M solution of it?

The weight of NaOH in a 100 ml 0. 1 M solution is 10 grams. This is because the molecular weight of NaOH is 40 g/mole and 0. 1 molar (M) solution means 0. 1 moles/L (or 0. 1 mol/1000 mL). To calculate the weight needed for a 0.

1 M solution, we multiply 0. 1 moles/L X 40 g/mole = 4 g/L. Finally, we multiply 4 g/L by the volume in liters (100 ml = 0. 1 L), which gives us 4 g/L X 0. 1 L = 0. 4 g or 10 grams of NaOH.

How to prepare 250 mL of 1M NaCl?

To prepare 250 mL of 1M NaCl, you will need 250 grams or 8. 8 ounces of table salt (sodium chloride, or NaCl). Place the salt into a large container and add enough distilled or deionized water to make a total of one liter (1000 mL) of solution.

Then carefully measure out 250 mL of the solution into a separate container and label it “1M NaCl”.

To help with the proper mixing of salt and water, use a stirring rod or spoon. Be sure to stir the solution until the salt is completely dissolved. Once the solution is completely mixed, check the solution to ensure the desired molar concentration of 1M is achieved.

The easiest way to do this is to measure the density of the solution with a hydrometer, which will give you an indication of the salt concentration. If the solution is not at 1M, continue to add salt to increase the concentration until you achieve the desired molarity.

How many grams of sodium hydroxide would you use to prepare a 250 mL of 0.6 M sodium hydroxide solution?

To calculate the amount of sodium hydroxide needed to prepare a 250 mL of 0.6 M sodium hydroxide solution, you would use the following equation:

grams of sodium hydroxide = (0.6 M)(0.25 L)(Na molar mass)

where, Na molar mass is the molar mass of sodium, which is 23.0 g/mol.

Therefore, the amount of grams of sodium hydroxide to prepare a 250 mL of 0.6 M sodium hydroxide solution would be:

grams of sodium hydroxide = (0.6 M)(0.25 L)(23.0 g/mol) = 3.9 g

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